1 molelcule of glucose forms _______ molecules of pyruvate?
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Answer: B. 2
Explanation
Glycolysis breaks down a six carbon glucose molecule into smaller units. Enzymatic cleavage splits the phosphorylated sugar into two three carbon molecules. These resulting three carbon molecules are known as pyruvate. Glycolysis is the initial metabolic pathway of cellular respiration in cells. The process occurs in the cytoplasm without requiring molecular oxygen. Net energy yield includes ATP and NADH molecules alongside the pyruvate.
Cellular respiration depends on glycolysis to supply pyruvate for the Krebs cycle. Cancer cells often rely heavily on glycolysis for rapid energy production. Biochemical pathways convert glucose into usable energy in all living organisms. Option A one molecule of pyruvate is incorrect due to carbon atom conservation. Option C three molecules would exceed the initial six carbon count of glucose. Option D four molecules contradicts the fundamental stoichiometry of glycolysis.
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