Two valves fill a container independently in 20 and 30 hours respectively. Opening both to fill the container, a fissure forms upon reaching full capacity, allowing one-third of the total supplied water to escape. Compute the cumulative duration required to fill the container?
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Answer: B. 16 hrs
Explanation
Valves filling a container independently in twenty and thirty hours have combined normal filling rates that establish baseline timing. A fissure forming at full capacity allows one third of the total supplied water to escape, requiring extra filling time. Accounting for both the standard filling duration and the water loss replacement time results in a cumulative duration of sixteen hours. Tank filling problems with leaks or fissures require calculating net water accumulation rates over operational periods. Volume loss fractions directly increase the total time needed to achieve stable container capacity targets. Cumulative duration calculations combine uninterrupted filling phases with interrupted leaking phases sequentially.
Eighteen hrs overestimates the cumulative duration by miscalculating the time needed to replace the escaped water volume. Fifteen hrs underestimates the total time because it ignores the extra water required to offset the fissure leakage. Twelve hrs represents an idealized filling time without any water loss or fissure complications whatsoever.
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- Mathematics
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- Mathematics
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- Difficulty
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