Three identical pipes fill a tank in 8 hours. If only two such pipes are used, in how much time will it fill___________?
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Answer: B. 12 hours
Explanation
Three identical pipes filling a tank in eight hours represent a total workload of twenty four pipe hours. The total amount of work required to fill the reservoir remains constant regardless of how many pipes operate. Dividing the total twenty four pipe hours of work by two active pipes yields a time of twelve hours. Work rate problems assume that identical contributors perform tasks at consistent and uniform rates over time. Multiplying the number of operational units by the completion time yields the total constant work in man hours or pipe hours. Inverse proportionality governs work and time relationships when the number of operational units changes.
Seventeen hours is mathematically inconsistent with the inverse proportion rule governing pipe work rates. Sixteen hours would incorrectly assume linear proportionality where fewer pipes take more than double the time. Twenty four hours assumes each pipe contributes only one hour of work rather than sharing the total load.
- Subject
- Mathematics
- Category
- Mathematics
- Topic
- —
- Difficulty
- medium
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