Moving at 6/7th of his standard velocity, a pedestrian arrives 12 minutes behind schedule. What is his usual duration to traverse that path?
Show answer Hide answer
Answer: D. 1 hr 12 min
Explanation
Moving at six-sevenths of standard velocity increases the required travel duration to seven-sixths of normal. The difference between seven-sixths and the standard duration equals exactly one-sixth of normal time. Equating one-sixth of the normal duration to twelve minutes reveals a total usual duration of seventy-two minutes. Travel time is inversely proportional to velocity when covering a constant distance between two fixed points. Multiplying twelve minutes by the denominator factor of six yields seventy-two total minutes of travel time. Converting seventy-two minutes into standard time format gives one hour and twelve minutes duration.
Transportation logistics planners use inverse speed-time relationships to schedule freight delivery windows accurately. Commuters adjust departure times when traffic congestion reduces average vehicle speeds below normal operating levels. Aviation dispatchers calculate flight duration adjustments resulting from reduced cruising speeds or headwind conditions. Option A suggests one hour and forty-two minutes which overstates the proportional time delay calculation. Option B proposes one hour which underestimates the actual normal duration required for the journey. Option C implies two hours which completely misinterprets the fractional time difference of twelve minutes.
- Subject
- Mathematics
- Category
- Mathematics
- Topic
- —
- Difficulty
- medium
Related questions
Q1. Calculate the metallic wire length necessary to encircle a square estate spanning 69696 m2 exactly 15 times.
Show answer Hide answer
Answer: A. 15840 m
Taking the square root of the given area yields the exact length of one square side. Multiplying the side length by four determines the total perimeter distance of the estate. Multiplying the single perimeter length by f...
Q2. If a solid spherical mass of 10 cm radius is reshaped into 8 identical solid spherical spheres, determine the surface area belonging to each sphere (in cm2)________?
Show answer Hide answer
Answer: A. 100π
The volume of a sphere scales with the cube of its radius, making the large sphere's volume proportional to 1000. Dividing this volume among eight identical smaller spheres gives each a proportional volume of 125, meanin...
Q3. An apartment measures 15m in length, 4m in width, and 3m in height. Compute the expense to apply whitewash across its four interior surfaces at a rate of 50p per m2?
Show answer Hide answer
Answer: B. Rs.57
The lateral surface area of the four interior walls equals one hundred fourteen square meters. Multiplying the total wall area by fifty paisa per square meter gives fifty seven rupees. The calculation accurately accounts...
Q4. An unsealed container measures 52, 40, and 29 cms externally with a 2 cms wall thickness. If 1 cm3 of the constituent metal weighs 0.5 gms, compute the total weight of the container________?
Show answer Hide answer
Answer: D. 6.832 kg
Subtracting double the wall thickness from each external dimension yields the internal container dimensions. Subtracting the internal volume from the external volume gives the exact volume of constituent metal. Multiplyi...
Q5. Determine the cardboard surface area (in cm2) required to construct a container measuring 25 cm * 15 cm * 8 cm__________?
Show answer Hide answer
Answer: A. 1390 cm2
Applying the rectangular box surface area formula multiplies the sum of length times breadth, breadth times height, and height times length by two. Calculating these products gives 375, 120, and 200, which sum to 695 squ...
Q6. Traveling at 80% of his normal pace, a worker arrives 10 minutes tardy at his workplace. Determine the standard time he takes to get to the office.
Show answer Hide answer
Answer: C. 40 minutes
Traveling at eighty percent speed means the pace is four fifths of the normal rate. Reduced speed increases the journey duration to five fourths of the standard time. The extra time equals one quarter of the standard tim...