Electrical Engineering is part of Engineering and holds 3,646 questions with answers, free to read and with no account needed.
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Answer: D. L/CR
At parallel resonance, the parallel tank circuit exhibits maximum resistive impedance across its input terminals. Mathematical derivation of this dynamic parallel impedance yields the standard engineering formula equal t...
Answer: B. 100.1 mA
The emitter current is mathematically equal to the sum of collector and base currents. Base current is calculated by dividing collector current by the given beta value of 100. Adding 10 mA and 0.1 mA yields 10.1 mA, expl...
Answer: B. silicon
Semiconductor manufacturing coding standards use specific letters like B to designate silicon as the base material. The letter C in the prefix indicates that the semiconductor device is designed to function as a low-freq...
Answer: A. ICEO
The equation incorporates the collector-emitter leakage current with the base current multiplied by gain. In common-emitter setups, this specific leakage term accounts for the current flowing with an open base. Without i...
Answer: A. ICBO
The complete collector current equation accounts for minority carrier leakage across the reverse-biased collector-base junction. This specific leakage current flowing when the emitter current is zero is designated by the...
Answer: A. Capacitive
When signal frequencies exceed resonance in a parallel LC circuit, capacitive reactance becomes smaller. Lower capacitive reactance allows more current to bypass the inductive branch of the circuit. Consequently the para...
Answer: A. 0.4 mm to 0.5 mm
Transformer core laminations are manufactured very thin to increase electrical resistance across potential eddy current paths. Keeping the thickness between 0.4 mm and 0.5 mm effectively suppresses circulating eddy curre...
Answer: D. 90
Beta is mathematically derived from alpha by dividing alpha by one minus alpha. Substituting an alpha value of zero point nine into this standard formula yields ninety. This relationship highlights how a small change in...
Answer: C. Is raised
Reducing mutual inductance between coupled coils decreases the magnetic coupling coefficient below the critical coupling threshold. As magnetic coupling drops below critical value, the double-tuned resonance curve loses...
Answer: A. decreases
Semiconductor material resistivity decreases as ambient temperature increases due to thermal excitation. Thermal energy generates additional free charge carriers within the semiconductor crystal lattice. This increase in...
Answer: D. None of the above
Class C amplifiers conduct for less than half of the input cycle, making them ideal for high-power radio frequency applications. The listed options provided lower power categories that do not encompass the high-power dom...
Answer: C. Selectivity
The quality factor of a tuned resonant circuit determines its bandwidth and frequency discrimination sharpness. A higher Q factor results in a narrower bandwidth, which directly improves the selectivity of the filter cir...
Answer: D. prevent excessive temperature rise
Active semiconductor devices generate internal thermal energy during continuous power dissipation and current conduction. Excessive temperature buildup can permanently degrade semiconductor junctions and destroy the inte...
Answer: B. two pn junctions
A standard bipolar junction transistor is constructed from three alternating semiconductor layers. These three regions consist of an emitter, a base, and a collector terminal connection. The junctions separating these th...
Answer: C. More than 10
Tuned amplifiers must isolate narrow frequency bands while rejecting unwanted adjacent signals in communication systems. Achieving this high degree of selectivity requires a quality factor significantly greater than 10....
