Two infinite parallel plates separated by 10 mm maintain a potential difference of 100 V. The resulting acceleration of an electron placed between them is______________?
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Answer: D. 1.76 x 1015 m/s2
Explanation
The electric field between the plates accelerates the electron based on its charge, mass, and field strength. Dividing voltage by plate separation yields the electric field, which then multiplies by electron charge and divides by mass. The resulting calculation confirms that option D correctly identifies the electron acceleration value. Electric field intensity equals potential difference divided by the distance separating the parallel plates. Newton's second law combined with electric force equations allows calculating particle acceleration in fields. Electron mass and elementary charge constants are fundamental values used in physics and electronics calculations.
Calculating electron acceleration is vital for designing cathode ray tubes, particle physics detectors, and electron microscopes. High acceleration values demonstrate how rapidly subatomic particles gain kinetic energy in electrostatic fields. Understanding beam dynamics ensures accurate focusing and deflection in vacuum tube electronic displays. Options A, B, and C provide incorrect acceleration values resulting from mathematical calculation errors. Incorrect mass or charge values in the force equation would yield erroneous tenth-power exponents. Precision in division and unit conversion is required to avoid selecting wrong acceleration magnitudes.
- Subject
- Engineering
- Category
- Electrical Engineering
- Topic
- —
- Difficulty
- medium
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