The electric field intensity at a point may be defined as equal to the lines of force passing normally through a unit cross section at that point ?
Show answer Hide answer
Answer: A. Electric intensity
Explanation
Electric intensity at any point corresponds numerically to the density of electric lines of force passing normally. Faraday conceptualized electric lines of force to visualize the magnitude and direction of electric fields. Field intensity magnitude equals the normal flux per unit cross-sectional area surrounding the point in question. Electric field intensity represents the force experienced by a unit positive test charge placed at that point. Electric flux lines originate on positive charges and terminate on negative charges within the electrostatic field. Vector fields like electric intensity require both magnitude and directional specifications to be fully understood.
Option B refers to magnetic flux density, which relates to magnetic fields rather than electrostatic fields. Option C denotes electric flux, representing the total count rather than the intensity per unit area. Option D is incorrect because electric intensity is the standard and correct term for this definition.
- Subject
- Engineering
- Category
- Electrical Engineering
- Topic
- —
- Difficulty
- medium
Related questions
Q1. A gang capacitor is a form of____________?
Show answer Hide answer
Answer: B. variable capacitor
A gang capacitor mechanically links multiple variable capacitors together on one single rotating shaft. Rotating the shared shaft alters the meshing plate area to change capacitance simultaneously. This mechanical arrang...
Q2. Which of the following substances features a lower specific gravity V__________?
Show answer Hide answer
Answer: C. Water
Pure water has a specific gravity of exactly one by definition at standard temperature conditions. Concentrated sulfuric acid and dilute solutions both have higher specific gravity values than pure water. Comparing densi...
Q3. A potential of 400 V is applied across capacitor plates spaced 4 mm apart. The resulting electric field strength is___________?
Show answer Hide answer
Answer: A. 100 kV/m
Electric field strength equals the applied potential difference divided by the distance between plates. Dividing four hundred volts by zero point zero four meters yields one hundred thousand volts per meter. Converting t...
Q4. Paper dielectric capacitors are commonly manufactured in the structural form of_____________?
Show answer Hide answer
Answer: B. rolled foil
Paper dielectric capacitors are manufactured by rolling long strips of metal foil and thin paper together. This rolled cylinder construction maximizes the effective surface area of the conductive plates compactly. Enclos...
Q5. The electric field intensity at a point is equal to the negative potential gradient at that point?
Show answer Hide answer
Answer: A. Electric intensity
Electric field intensity is mathematically defined as the negative gradient of the electric potential. The directional derivative of potential points toward the steepest rate of change in voltage. This fundamental relati...
Q6. A positive and a negative charge are initially 50 mm apart. When brought closer to a distance of 10 mm, the electrostatic force between them becomes________________?
Show answer Hide answer
Answer: D. 25 times larger than before
Electrostatic force is inversely proportional to the square of the distance separating the charges. Reducing the distance from fifty millimeters to ten millimeters decreases the separation by a factor of five. Squaring t...