For a non-flow reversible process governed by p = (- 3V+ 15) x 105N/m2, where V shifts from 1 m to 2 m3, the work performed will approximately be_______________?
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Answer: C. 10 xlO5 joules
Explanation
Work done in a non-flow process is calculated by integrating the pressure-volume function. Integrating the given linear pressure expression between limits yields the exact energy value. Mathematical evaluation of the definite integral results in ten times ten to the fifth Joules. Non-flow work represents boundary work done by a gas expanding or compressing in a closed system. Calculus integration determines the area under the pressure-volume curve during a thermodynamic process. Standard SI units ensure work output calculates correctly in Joules or Newton-meters.
Thermodynamic cycle analysis requires evaluating boundary work during piston expansion strokes. Engineers use pressure-volume integration to calculate indicated work output in machinery. Accurate work calculations are essential for evaluating compressor and expander performance. Option A overestimates the calculated work integral by a factor of ten. Option B and D feature incorrect magnitude scaling and unit designations. Option E provides mismatched exponent values that fail the integration mathematical result.
- Subject
- Engineering
- Category
- Mechanical Engineering
- Topic
- —
- Difficulty
- medium
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