For a full-wave rectifier using ideal diodes, letting Vdc and Vm denote DC and peak load voltages while PIV represents peak inverse voltage, the proper relationship is____________?
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Answer: B. Vdc = 2Vm/π, PIV=2vm
Explanation
For an ideal full-wave rectifier, the average DC load voltage equals two times the peak voltage divided by pi. During each half-cycle, diodes conduct current in the same direction through the load resistor without interruption. The peak inverse voltage across each non-conducting diode must withstand twice the peak input voltage safely. Full-wave rectification utilizes both halves of the alternating current sine wave to produce a pulsating direct current. Mathematical integration of the rectified sine wave yields an average DC voltage value of approximately sixty-three percent. Peak inverse voltage represents the maximum reverse voltage stress a diode experiences while in the off state.
Vdc equal to Vm over pi describes a half-wave rectifier rather than a full-wave bridge configuration. PIV equal to Vm represents the maximum voltage stress found in center-tapped transformer rectifier circuits. Mixed formulations with incorrect coefficients violate fundamental AC circuit integration and diode bridge principles.
- Subject
- Engineering
- Category
- Electrical Engineering
- Topic
- —
- Difficulty
- medium
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