A metallic object measuring 3 kg in air registers 2.5 kg when completely immersed in water. What is its specific gravity_________________?
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Answer: D. 6
Explanation
Specific gravity is calculated as the weight of an object in air divided by its apparent loss in water. The weight of the object in air is three kilograms, while its immersed weight is two point five kilograms. Dividing three by the weight loss of zero point five results in a specific gravity of six. Archimedes principle states that a completely immersed object experiences an upward buoyant force equal to displaced water weight. Apparent loss of weight in water equals the weight in air minus the immersed weight value. Specific gravity is a dimensionless ratio comparing material density to the density of pure water.
Option A is incorrect because a specific gravity of one indicates floating density equal to water. Option B results from an incorrect subtraction or division error during the calculation steps. Option C represents an incorrect arithmetic result that does not match the buoyant force ratio.
- Subject
- Engineering
- Category
- Mechanical Engineering
- Topic
- —
- Difficulty
- medium
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